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If the price in beginning of paragraph always, you can use this:
(?s)^\$?\K\d[.\d]+
I think there is a forced line break or non breaking space.
Try to do this by GREP tab in Find/Change window:
To replace forced line with normal space:
in Find:
in Change:
To delete non breaking space:
in Find: ~S
in Change: leave empty (Do not put anything)
and tell us what happened
Hello! Your regex finds set of parentheses only in the end of paragraph, but my regex finds find the last set in anywhere
\([^)]+\)$
\( open parentheses
[^)] any character except the close parentheses (this form is called negated character set)
+ one time and more (but you should use here +? to make it shortest match)
\) close parentheses
$ end of paragraph
.*\K\(.+?\)
. any character
* zero or more times
\K keep all the before outside the matching
\(.+?\) the same above
To find every last set of parentheses use this: .*\K\(.+?\)
Try to use “Space Between Paragraphs Using Same Style” option and make it “0”
You can use this in GREP Style with superscript Character Style \d\K?(th|st|nd|rd)\> or this (?<=\d)\p{zs}?(th|st|nd|rd)\>
Or this:
+(?=\r)
Try this:
(?s)~b+(?=\r)
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