Your English is fine — I bet it's better than my Peruvian (:D)
The trick is to search for any string of digits, just as long as the very last one is odd (or even). Try this:
bd+[13579]b
The b marks a word boundary — that is, when at the left of a 'word character', there may not be another word character; it's the same when it's to the right of a 'word character'.
d+ is any digit, and the + means you can have one or lots of them.
[13579] means any single character in this set, so it will match '1' or '3' but not '2' or '?' or 'a'.
Then another b follows, to ensure this is the very last character in the search string and no other word character follows.
(A 'word character' is, according to InDesign, 0 to 9, A to Z and a to z, as well as all accented characters, and even the alphabetical characters in Greek, Cyrillic, and many more. It's by definition not anything like a space or punctuation — anything that separates words from each other.)