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Grep question

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    • May 6, 2010 at 6:27 pm #55653
      Massey Padgham
      Member

      How can I select any comma that is preceded by at least 14 uppercase,lowercase letters and/or spaces

      I can do it with a positive lookbehind for 14 but can't figure out the syntax for 14 OR MORE

      Thanks

    • May 7, 2010 at 1:49 am #55654
      Theunis De Jong
      Member

      Lookbehind does not accept variable length arguments — you cannot use “+”, “?”, “*”, or any value x other than n in “{n,[x]}”. You can only group together multiple fixed-length lookbehinds like this:

      ((?<=[ul ]{14})|(?<=[ul ]{15})),

      But I don't think it's necessary — if you already found 14, why would you want to test if there are even more?

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