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GREP expression for commas

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    • November 20, 2016 at 8:36 pm #89921
      Gregory Perry
      Member

      I need to come up with a code in GREP to search for any letter that is followed by a standard carriage return followed by a letter or character other than a period. I need to replace everything except the standard carriage return. I can do most of this with the exception of the comma. I haven’t been able to figure out what expression or code to use to locate and keep a comma in GREP in the replacement text () followed by $#. I tried using just comma but that didn’t work. Can someone help me out please?

    • November 21, 2016 at 2:17 am #89922
      Kai Rübsamen
      Member

      Gregory, this sounds easy, but needs maybe a bit more explanation.

      However:
      The first character after a carriage return: \r\K[^.]
      All characters after a carriage return, that are not a period: \r\K[^.]+

      This will find also a return after a return and maybe too much …

      Kai

    • November 21, 2016 at 8:45 am #89947
      Gregory Perry
      Member

      Perfect, I can add that to what I already know. Thanks for the help.

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