Hey, Hank, I did not notice that 'in a certain character style'! ('dans une certaine condition', perhaps)

Add this line somewhere after the findWhat line:

  app.findGrepPreferences.appliedCharacterStyle = “YourCharacterStyleNameHere“;

to search for just those numbers. The rest of the script is, unlikely as it may sound, totally unaffected by this change — it merely now finds, and optionally changes, numbers that have the style applied.

Hank, I don't have the remotest idea how you think it would add 1 to any of these numbers …

David is right, of course — GREP Is Not Magic. It cannot do calculations, nor can it search an item from a list[*] and replace it with an equivalent from another list. You cannot have a similar list in the replace field.

[*] Well, it can, using the OR | operator, but “Replace” doesn't know which item it found.

Also, you can enter a 'range' in the Find field in the form [a-z] — this will find anything from 'a' to 'z'. But GREP does not know maths — you cannot search for [69-82]. (Go ahead, try. You will see it treats this as '6', '9-8', and '2' — and its anybodies guess what it will do with the malformed range in the middle.)

A script to search and change the numbers in your range could be something like this (a rough attempt but it seems to work):

//DESCRIPTION: Change some numbers and leave some else. In a selection as well.

// A Jongware production. No guarantees.

var ranges = [

[54, 103, 1],

[104, 178, 2]

];

// step 0: verify selection

if (app.selection.length != 1)

{

alert (“Well, I warned you to select something!”);

exit();

}

// step 1: find ALL numbers

app.findChangeGrepOptions = null;

app.findGrepPreferences = null;

app.findGrepPreferences.findWhat = “\d+”;

numberList = app.selection[0].findGrep(true);

// alert ('found '+numberList.length);

// step 2: change certain ranges

for (a=0; a<numberList.length; a++)

{

thisVal = Number(numberList[a].contents);

for (b=0; b<ranges.length; b++)

{

if (thisVal >= ranges[b][0] && thisVal <= ranges[b][1])

{

numberList[a].contents = String(thisVal+ranges[b][2]);

break;

}

}

}

// step 3: … erm. That's all!

Hank, I don't have the remotest idea how you think it would add 1 to any of these numbers …

David is right, of course — GREP Is Not Magic. It cannot do calculations, nor can it search an item from a list[*] and replace it with an equivalent from another list. You cannot have a similar list in the replace field.

[*] Well, it can, using the OR | operator, but “Replace” doesn't know which item it found.

Also, you can enter a 'range' in the Find field in the form [a-z] — this will find anything from 'a' to 'z'. But GREP does not know maths — you cannot search for [69-82]. (Go ahead, try. You will see it treats this as '6', '9-8', and '2' — and its anybodies guess what it will do with the malformed range in the middle.)

A script to search and change the numbers in your range could be something like this (a rough attempt but it seems to work):

//DESCRIPTION: Change some numbers and leave some else. In a selection as well.

// A Jongware production. No guarantees.

var ranges = [

[54, 103, 1],

[104, 178, 2]

];

// step 0: verify selection

if (app.selection.length != 1)

{

alert (“Well, I warned you to select something!”);

exit();

}

// step 1: find ALL numbers

app.findChangeGrepOptions = null;

app.findGrepPreferences = null;

app.findGrepPreferences.findWhat = “bd+b”;

numberList = app.selection[0].findGrep(true);

// alert ('found '+numberList.length);

// step 2: change certain ranges

for (a=0; a<numberList.length; a++)

{

thisVal = Number(numberList[a].contents);

for (b=0; b<ranges.length; b++)

{

if (thisVal >= ranges[b][0] && thisVal <= ranges[b][1])

{

numberList[a].contents = String(thisVal+ranges[b][2]);

break;

}

}

}

// step 3: … erm. That's all!

You can make a list of the different spellings and put that into the standard FindChangeByList script — that'll take care of 'realise', 'colour', 'mailbox', and their 'ilk' ('like').

For the 'grammar', however, it's unlikely one will ever find a computerized solution. It would boil down to translating from one language to another. If you check Google Translate, you will see their only choice is plain 'English' — no dialects available.

Roland, this “script” (it's a single line!) will convert all tables to text, separating the columns by a comma, and the rows by a hard return. It's a javascript, so save it with a “.jsx” extension.

app.activeDocument.stories.everyItem().tables.everyItem().convertToText (",", "r");

Roland, this “script” (it's a single line!) will convert all tables to text, separating the columns by a comma, and the rows by a hard return. It's a javascript, so save it with a “.jsx” extension.

app.activeDocument.stories.everyItem().tables.everyItem().convertToText (",", "\r");

@Jesserenko Yes, GREP would certainly do what I want, especially if I can figure out how to keep double returns from being replaced so I won't lose the true paragraph return. 

Try this: (?<=[^\r]) *\r(?=[^\r]) — replace with a single space.

In its essence, it should search for at-left-not a return, any number of regular spaces (including none at all), a single return, at-right-not a return.

Since copy-and-paste often introduces some space before carriage returns, you need to allow for zero or more spaces before that return.