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– EDIT you dont want the space at the end
\<\w(?=\w{3,})
GREP style : CAPS
\<\w(?=\w{3,})
Change first letter of any word larger than 3 letters
(It is not perfect)
Thanks David that would help me to solve the problem – However I have just had a Eureka moment …
So my target was to define “find any white space except a forced line break” as part of a wider find / change:
I want to find all instances of a pipe “|” and make sure that it is surrounded by a space on both sides – ” | ”
I do not want to select a forced line break if there is one
So I did this = (?<=.)*?\|*?(?=*\w) and replace with ” | “
My helpful grep style codes:
(?<=m)2
superscript m²
[\(“‘].+?[‘”\)](?=[[:punct:]]|)
Apply any style to any text inside ( ) or ” ” or ‘ ‘ – included in this code is to ignore the instance of an apostrophe that is not followed by any white space
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