Reply To: force line break after 50 caracters

May 19, 2017 at 1:58 am #94770

Participant

Yeap! It will take time! 1 second! =D

Find: .{49}\K.
Replace by: $0

… if you consider a space as a char!

If not, you’ll need more regex (3 if you consider all spaces as same ones) and more time! Maybe 2 op-seconds! =D

Find:
Replace ~j

Find: .{49}\K.
Replace by: $0

Find: ~j
Replace by:
(type a normal space)

(^/)

This article was last modified on May 19, 2017

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